Selecting elements from lists based on string pattern
1
$begingroup$
I have a list:
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}
I would like to select list items that have first elements that end in the string "bc" to give:
res = {{1,2},{5,6}}
This is a variant on this question which has to do with strings only. Thank you as always for suggestions.
list-manipulation string-manipulation
asked 3 hours ago
Suite401Suite401
988312
$endgroup$
add a comment |
1
$begingroup$
I have a list:
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}
I would like to select list items that have first elements that end in the string "bc" to give:
res = {{1,2},{5,6}}
This is a variant on this question which has to do with strings only. Thank you as always for suggestions.
list-manipulation string-manipulation
asked 3 hours ago
Suite401Suite401
988312
$endgroup$
add a comment |
1
1
1
$begingroup$
I have a list:
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}
I would like to select list items that have first elements that end in the string "bc" to give:
res = {{1,2},{5,6}}
This is a variant on this question which has to do with strings only. Thank you as always for suggestions.
list-manipulation string-manipulation
asked 3 hours ago
Suite401Suite401
988312
$endgroup$
I have a list:
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}
I would like to select list items that have first elements that end in the string "bc" to give:
res = {{1,2},{5,6}}
This is a variant on this question which has to do with strings only. Thank you as always for suggestions.
list-manipulation string-manipulation
list-manipulation string-manipulation
asked 3 hours ago
Suite401Suite401
988312
asked 3 hours ago
Suite401Suite401
988312
asked 3 hours ago
Suite401Suite401
988312
asked 3 hours ago
Suite401Suite401
988312
asked 3 hours ago
Suite401Suite401
988312
988312
add a comment |
add a comment |
3 Answers
3
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oldest
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2
$begingroup$
Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]
{{1, 2}, {5, 6}}
Also
f[{_String?(StringEndsQ["bc"]), x__}] := {x}
f[_] := Sequence
f /@ lis
{{1, 2}, {5, 6}}
answered 23 mins ago
kglrkglr
181k10200413
$endgroup$
add a comment |
1
$begingroup$
This uses string matching on the first element of each sublist and then discards the first element from the matches.
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
(* {{1, 2}, {5, 6}} *)
You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.
answered 2 hours ago
BillBill
5,62569
$endgroup$
add a comment |
1
$begingroup$
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Using Cases
Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y},
Infinity]
(* {{1, 2}, {5, 6}} *)
or
Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
(* {{1, 2}, {5, 6}} *)
Or using Select
Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
(* {{1, 2}, {5, 6}} *)
Or using DeleteCases
Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __},
Infinity]
(* {{1, 2}, {5, 6}} *)
answered 1 hour ago
Bob HanlonBob Hanlon
59.5k33596
$endgroup$
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
$begingroup$
Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]
{{1, 2}, {5, 6}}
Also
f[{_String?(StringEndsQ["bc"]), x__}] := {x}
f[_] := Sequence
f /@ lis
{{1, 2}, {5, 6}}
answered 23 mins ago
kglrkglr
181k10200413
$endgroup$
add a comment |
2
$begingroup$
Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]
{{1, 2}, {5, 6}}
Also
f[{_String?(StringEndsQ["bc"]), x__}] := {x}
f[_] := Sequence
f /@ lis
{{1, 2}, {5, 6}}
answered 23 mins ago
kglrkglr
181k10200413
$endgroup$
add a comment |
2
2
2
$begingroup$
Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]
{{1, 2}, {5, 6}}
Also
f[{_String?(StringEndsQ["bc"]), x__}] := {x}
f[_] := Sequence
f /@ lis
{{1, 2}, {5, 6}}
answered 23 mins ago
kglrkglr
181k10200413
$endgroup$
Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]
{{1, 2}, {5, 6}}
Also
f[{_String?(StringEndsQ["bc"]), x__}] := {x}
f[_] := Sequence
f /@ lis
{{1, 2}, {5, 6}}
answered 23 mins ago
kglrkglr
181k10200413
answered 23 mins ago
kglrkglr
181k10200413
answered 23 mins ago
kglrkglr
181k10200413
answered 23 mins ago
kglrkglr
181k10200413
181k10200413
add a comment |
add a comment |
1
$begingroup$
This uses string matching on the first element of each sublist and then discards the first element from the matches.
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
(* {{1, 2}, {5, 6}} *)
You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.
answered 2 hours ago
BillBill
5,62569
$endgroup$
add a comment |
1
$begingroup$
This uses string matching on the first element of each sublist and then discards the first element from the matches.
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
(* {{1, 2}, {5, 6}} *)
You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.
answered 2 hours ago
BillBill
5,62569
$endgroup$
add a comment |
1
1
1
$begingroup$
This uses string matching on the first element of each sublist and then discards the first element from the matches.
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
(* {{1, 2}, {5, 6}} *)
You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.
answered 2 hours ago
BillBill
5,62569
$endgroup$
This uses string matching on the first element of each sublist and then discards the first element from the matches.
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
(* {{1, 2}, {5, 6}} *)
You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.
answered 2 hours ago
BillBill
5,62569
answered 2 hours ago
BillBill
5,62569
answered 2 hours ago
BillBill
5,62569
answered 2 hours ago
BillBill
5,62569
5,62569
add a comment |
add a comment |
1
$begingroup$
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Using Cases
Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y},
Infinity]
(* {{1, 2}, {5, 6}} *)
or
Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
(* {{1, 2}, {5, 6}} *)
Or using Select
Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
(* {{1, 2}, {5, 6}} *)
Or using DeleteCases
Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __},
Infinity]
(* {{1, 2}, {5, 6}} *)
answered 1 hour ago
Bob HanlonBob Hanlon
59.5k33596
$endgroup$
add a comment |
1
$begingroup$
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Using Cases
Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y},
Infinity]
(* {{1, 2}, {5, 6}} *)
or
Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
(* {{1, 2}, {5, 6}} *)
Or using Select
Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
(* {{1, 2}, {5, 6}} *)
Or using DeleteCases
Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __},
Infinity]
(* {{1, 2}, {5, 6}} *)
answered 1 hour ago
Bob HanlonBob Hanlon
59.5k33596
$endgroup$
add a comment |
1
1
1
$begingroup$
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Using Cases
Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y},
Infinity]
(* {{1, 2}, {5, 6}} *)
or
Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
(* {{1, 2}, {5, 6}} *)
Or using Select
Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
(* {{1, 2}, {5, 6}} *)
Or using DeleteCases
Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __},
Infinity]
(* {{1, 2}, {5, 6}} *)
answered 1 hour ago
Bob HanlonBob Hanlon
59.5k33596
$endgroup$
lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
Using Cases
Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y},
Infinity]
(* {{1, 2}, {5, 6}} *)
or
Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
(* {{1, 2}, {5, 6}} *)
Or using Select
Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
(* {{1, 2}, {5, 6}} *)
Or using DeleteCases
Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __},
Infinity]
(* {{1, 2}, {5, 6}} *)
answered 1 hour ago
Bob HanlonBob Hanlon
59.5k33596
answered 1 hour ago
Bob HanlonBob Hanlon
59.5k33596
answered 1 hour ago
Bob HanlonBob Hanlon
59.5k33596
answered 1 hour ago
Bob HanlonBob Hanlon
59.5k33596
59.5k33596
add a comment |
add a comment |
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