How can I have x-axis ticks that show ticks scaled in powers of ten?
1
$begingroup$
I am having trouble achieving this effect with on the x-axis. Does anybody have an idea how I can achieve this effect?
plotting
edited 18 mins ago
m_goldberg
87.4k872198
asked 2 hours ago
Kanye WestKanye West
112
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$endgroup$
add a comment |
1
$begingroup$
I am having trouble achieving this effect with on the x-axis. Does anybody have an idea how I can achieve this effect?
plotting
edited 18 mins ago
m_goldberg
87.4k872198
asked 2 hours ago
Kanye WestKanye West
112
New contributor
Kanye West is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$
$begingroup$
Use theTicksoption. Some code showing what you want to plot and perhaps what you have tried would help.
$endgroup$
– Michael E2
1 hour ago
1
$begingroup$
As a slight correction to kglr's comment: the "number theory" version of the logarithmic integral is expressed asLogIntegral[x] - LogIntegral[2].
$endgroup$
– J. M. is computer-less♦
1 hour ago
add a comment |
1
1
1
$begingroup$
I am having trouble achieving this effect with on the x-axis. Does anybody have an idea how I can achieve this effect?
plotting
edited 18 mins ago
m_goldberg
87.4k872198
asked 2 hours ago
Kanye WestKanye West
112
New contributor
Kanye West is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I am having trouble achieving this effect with on the x-axis. Does anybody have an idea how I can achieve this effect?
plotting
plotting
edited 18 mins ago
m_goldberg
87.4k872198
asked 2 hours ago
Kanye WestKanye West
112
New contributor
Kanye West is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 18 mins ago
m_goldberg
87.4k872198
asked 2 hours ago
Kanye WestKanye West
112
New contributor
Kanye West is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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edited 18 mins ago
m_goldberg
87.4k872198
edited 18 mins ago
m_goldberg
87.4k872198
edited 18 mins ago
m_goldberg
87.4k872198
87.4k872198
asked 2 hours ago
Kanye WestKanye West
112
New contributor
Kanye West is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
Kanye WestKanye West
112
asked 2 hours ago
Kanye WestKanye West
112
112
New contributor
Kanye West is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Kanye West is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Kanye West is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
Use theTicksoption. Some code showing what you want to plot and perhaps what you have tried would help.
$endgroup$
– Michael E2
1 hour ago
1
$begingroup$
As a slight correction to kglr's comment: the "number theory" version of the logarithmic integral is expressed asLogIntegral[x] - LogIntegral[2].
$endgroup$
– J. M. is computer-less♦
1 hour ago
add a comment |
$begingroup$
Use theTicksoption. Some code showing what you want to plot and perhaps what you have tried would help.
$endgroup$
– Michael E2
1 hour ago
1
$begingroup$
As a slight correction to kglr's comment: the "number theory" version of the logarithmic integral is expressed asLogIntegral[x] - LogIntegral[2].
$endgroup$
– J. M. is computer-less♦
1 hour ago
$begingroup$
Use the
Ticks option. Some code showing what you want to plot and perhaps what you have tried would help.$endgroup$
– Michael E2
1 hour ago
$begingroup$
Use the
Ticks option. Some code showing what you want to plot and perhaps what you have tried would help.$endgroup$
– Michael E2
1 hour ago
1
1
$begingroup$
As a slight correction to kglr's comment: the "number theory" version of the logarithmic integral is expressed as
LogIntegral[x] - LogIntegral[2].$endgroup$
– J. M. is computer-less♦
1 hour ago
$begingroup$
As a slight correction to kglr's comment: the "number theory" version of the logarithmic integral is expressed as
LogIntegral[x] - LogIntegral[2].$endgroup$
– J. M. is computer-less♦
1 hour ago
add a comment |
1 Answer
1
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5
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LogLinearPlot[{PrimePi[x]/(LogIntegral[x]-LogIntegral[2]),
PrimePi[x]/(x/Log[x])}, {x, 2, 10000000}, GridLines -> {None, {1}}]
Thanks: @J.M.iscomputer-less for the LogIntegral[2] correction.
answered 1 hour ago
kglrkglr
187k10203421
$endgroup$
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
5
$begingroup$
LogLinearPlot[{PrimePi[x]/(LogIntegral[x]-LogIntegral[2]),
PrimePi[x]/(x/Log[x])}, {x, 2, 10000000}, GridLines -> {None, {1}}]
Thanks: @J.M.iscomputer-less for the LogIntegral[2] correction.
answered 1 hour ago
kglrkglr
187k10203421
$endgroup$
add a comment |
5
$begingroup$
LogLinearPlot[{PrimePi[x]/(LogIntegral[x]-LogIntegral[2]),
PrimePi[x]/(x/Log[x])}, {x, 2, 10000000}, GridLines -> {None, {1}}]
Thanks: @J.M.iscomputer-less for the LogIntegral[2] correction.
answered 1 hour ago
kglrkglr
187k10203421
$endgroup$
add a comment |
5
5
5
$begingroup$
LogLinearPlot[{PrimePi[x]/(LogIntegral[x]-LogIntegral[2]),
PrimePi[x]/(x/Log[x])}, {x, 2, 10000000}, GridLines -> {None, {1}}]
Thanks: @J.M.iscomputer-less for the LogIntegral[2] correction.
answered 1 hour ago
kglrkglr
187k10203421
$endgroup$
LogLinearPlot[{PrimePi[x]/(LogIntegral[x]-LogIntegral[2]),
PrimePi[x]/(x/Log[x])}, {x, 2, 10000000}, GridLines -> {None, {1}}]
Thanks: @J.M.iscomputer-less for the LogIntegral[2] correction.
answered 1 hour ago
kglrkglr
187k10203421
edited 1 hour ago
answered 1 hour ago
kglrkglr
187k10203421
answered 1 hour ago
kglrkglr
187k10203421
answered 1 hour ago
kglrkglr
187k10203421
187k10203421
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$begingroup$
Use the
Ticksoption. Some code showing what you want to plot and perhaps what you have tried would help.$endgroup$
– Michael E2
1 hour ago
1
$begingroup$
As a slight correction to kglr's comment: the "number theory" version of the logarithmic integral is expressed as
LogIntegral[x] - LogIntegral[2].$endgroup$
– J. M. is computer-less♦
1 hour ago